Tickets for a high school dance cost $1.00 each of purchased in advance of the dance, but $1.50 each if bought at the door. if 100 tickets were sold and $120 was collected, how many tickets were sold in advance and how many were sold at the door?

Tickets were sold in advance are 60 and the tickets were sold at the door are 40.

Step-by-step explanation:

Given:

Tickets for a high school dance.

Cost $1.00 each of purchased in advance of the dance.

Cost $1.50 each if bought at the door.

100 tickets were sold and $120 was collected.

Now, to find the tickets that were sold in advance and sold at the door.

Let the number of tickets sold in advance be .

And the number of tickets sold at the door be .

So, the total number of tickets sold:

......(1)

Now, the total amount collected:

Putting the equation (1) in the place of we get:

Adding both sides by we get:

Subtracting both sides by 120 we get:

Dividing 0.5 by both sides we get:

Thus, the number of tickets sold in advance = 60.

Putting the value of in equation (1) we get:

So, the number of tickets sold at the door = 40.

Therefore, tickets were sold in advance are 60 and tickets were sold at the door are 40.

easy math just plug in a and b

step-by-step explanation:

i dont know sorry

step-by-step explanation: