Given: m∥n , m∠1=65∘ , m∠2=60∘ , and bd−→− bisects ∠abc . prove: m∠6=70∘

it is given that m∥n , m∠1=65∘ , m∠2=60∘ , and bd−→− bisects ∠abc . because of the triangle sum theorem, m∠3=55∘ . by the ∠3≅∠4 , so m∠4=55∘ . using the m∠abc=110∘ . m∠5=110∘ because vertical angles are congruent. because of the m∠5+m∠6=180∘ . substituting gives 110∘+m∠6=180∘ . so, by the m∠6=70∘ .

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

pls mark as brainliest

the first one

step-by-step explanation:

just id the test.

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.