There are some nickels dimes and quarters in a large piggy bank. for every two nickels there are three dimes. for every two dimes there are 5 quarters. there are 500 coins total. how many nickels dimes and quarters are in the piggy bank. how much are the coins in the piggy bank worth.

The number of coins each are 120 dimes, 80 nickels and 300 quarters. And the coins worth dimes →$12, nickels →$4 and quarters →$75.

Step-by-step explanation:

Given:

For every two nickels there are three dimes. For every two dimes There are 5 Quarters. There are 500 coins total.

Now, to find the number of nickels, dimes and quarters. And the coins worth.

Let the number of dimes be .

The the number of nickels be .

And the number of quarters be .

So, the number of total coins are:

.........(1)

Now, as per given in question:

On solving we get:

.........(2)

On solving we get:

.........(3)

Now, in equation(1) substituting the equation (2) and(3) in the place of we get:

On solving the equation we get:

Multiplying both sides by 6 we get:

Dividing both sides by 25 we get:

Number of dimes = 120.

Putting the value of in equation 2 we get:

On solving we get:

The number of nickels = 80.

Now, putting the value of and in equation 1 we get:

On solving we get:

The number of quarters = 300.

Now, the coins worth:

Therefore, the number of coins each are 120 dimes, 80 nickels and 300 quarters. And the coins worth dimes →$12, nickels →$4 and quarters →$75.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3