A.) write the quadratic equation that has the roots, *the square root of 3* plus 1 all divided by 2, and *the square root of 3* minus 1 divided by 2, if its coefficient with x^2 is equal to 1.
b.) …has the coefficient with x^2 equal to -1/2.
c.) write the quadratic equation that has the roots, 2 minus *the square root of 3* and 1 divided by 2 minus *the square root of 3*, if its coefficient with x^2 is equal to 1.
d.) coefficient = 3/8

provide an explanation for problem a and problem c.

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)