Will mark brainliest, i'm having some trouble (question in attachment)

45b^4/32

Step-by-step explanation: First multiply the two fractions

15b^3y(3b)/8y x 4

Multiply 3 by 15

45b^3yb/8y x 4

Raise b to power of 1

45(b^1b^3)y/8y x 4

Use power rule to combine exponents

45b^1+3 y/8y x 4

Simplify

45b^4y/32y

Cancel common factor of y

45b^4/32

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.