Acoin collector has 31 dimes and nickels with a total face value of $2.40. (they are actually worth a lot more.) how many of each coin does she have?

The number of each coin she have are 17 dimes and 14 nickels.

Step-by-step explanation:

Given:

A coin collector has 31 dimes and nickels with a total face value of $2.40.

Now, to find each does she have.

Let the number of dimes be .

Let the number of nickels be .

So, total number of coins are:

Value of a dime = 10 cents

Value of a nickel = 5 cents

Total face value = 240 cents

(1$ = 100 cents.  $2.40×100 =240 cents)

Now, total value of coins:

Putting the equation (1) in the place of :

Moving variables on one side and the numbers on other:

Dividing both sides by 5 we get:

The number of nickels = 14.

Now, putting the value of in equation (1) we get:

Subtracting both sides by 14 we get:

The number of dimes = 17.

Therefore, the number of each coin she have are 17 dimes and 14 nickels.

i believe the correct answer is b.

in 2010, the population of the state of california is 37.29 × 10⁶

step-by-step explanation:

population of los angeles = 3.79 × 10⁶

population of california = 9.84 × population of los angeles

                                        = 9.84 × 3.79 × 10⁶

                                        = 37.2936 × 10⁶

                                        = 37.29 × 10⁶

∴ in 2010, the population of the state of california is 37.29 × 10⁶