Find the initial value aa, growth/decay factor bb, and growth/decay rate rr for the following exponential function: q(t)=0.0019(2.22)−3t q(t)=0.0019(2.22)−3t (a) the initial value is a=a= (numbers) (b) the growth factor is b=b= (numbers) (retain at least four decimal places.) (c) the growth rate is r=r= % (numbers) (ensure your answer is accurate to at least the nearest 0.01%) (note that if rr gives a decay rate you should have r< 0r< 0.)

a) 0.0019

b) 0.0913

c) 9.13%

Step-by-step explanation:

We are given the following information in the question:

The standard form of exponential function is

where a is the initial amount and b is the base.

Rewriting the the given function, we have:

a) Initial Value

Putting t = 0, we get,

a = 0.0019

b) Growth factor

Comparing, we get, b = 0.0913

c) Growth rate

chicken chicken chicken

step-by-step explanation:

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23