Suppose we have a binomial experiment with n= 40 trials and a probability of success p= 0.50.is it appropriate to use a normal approximation normal distribution? why? compute µ and of the approximation normal distribution. use a continuity correction factor to convert the statement r≥23 successes to a statement about the corresponding normal variable x. estimate p(r≥23)is it unusual for a binomial experiment with 40 trials and probability of success to 0.50 to have a 23 or more successes? explain.

We can approximate to normal.

The parameters of the approximate normal distribution are:

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

Step-by-step explanation:

To approximate the binomial distribution to a normal distribution, we can calculate n*p and n*q and if both are bigger than 5 we can do the approximation.

We can approximate to normal.

The parameters of the approximate normal distribution are:

The continuity correction factor is used because the binomial is a discrete function and the normal a continous function.

The probability of 23 successes must be expressed in the normal distribution as:

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

1.5%

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3