What is the equation of the line through (6, 3) and perpendicular to y=-x+2?
o y=-x-5
o y= ģx+2
o y= ge-5
o y=-x+

B. gx+2

Step-By-Step Explanation : Fund the negative reciprocal of the slope and the original line and use the point-slope formula y=y1=m(x-x1) to find the line perpendicular to y=-x+2.

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x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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