The centroid of any triangle is located at the point of intersection of the medians. recall that a median is a line segment from a vertex to the midpoint of the opposite side. recall also that the medians intersect at a point two-thirds of the way from each vertex (along the median) to the opposite side. find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles (from the above information) and using additivity of moments.

it has changed from the width and the height.

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

5

step-by-step explanation: