Therefore, a(s) = 1 + (−3)2 + (−2)2 da d = 14 da. d since we want the area of the section of the plane that lies above the first octant, then the region d will be the triangular region bounded by the x-axis, the y-axis, and the line formed by the intersection of the plane with the plane z = 0. substituting z = 0 into 3x + 2y + z = 6 and solving for y, we find that this line of intersection has the equation

Arepresentative from plan 1 wants to use the graph below to sell health plans for his company. how might the graph be redrawn to emphasize the difference between the cost per doctor visit for each of the three plans? the scale on the y-axis could be changed to 0–100. the scale on the y-axis could be changed to 25–40. the interval of the y-axis could be changed to count by 5s. the interval of the y-axis could be changed to count by 20s.