The sum of 5 consecutive even numbers is 20

Step-by-step explanation:

Let the 1st number be x

2nd number = x + 2

3rd number = x + 4

4th number = x + 6

5th number = x + 8

x + x + 2 + x + 4 + x + 6 + x + 8 = 20

5x + 20 = 20

5x = 20 - 20

5x = 0

x = 0 ÷ 5

x = 0

The 5 consecutive integers are

0, 2, 4, 6, 8

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.