Evaluate (1/3+1/4++1/2009)(1+1/2++1/+1/3+1/4 ++1/2009)(1/2+1/3++1/2008)

-2007/4018

Step-by-step explanation:

1. Given

(1/3+1/4+...+1/2009)(1+1/2+...1/2008) - (1+1/3+1/4+...+1/2009)(1/2+1/3+...+1/2008)

2. Set new variable

k = 1/3+1/4+...+1/2008

3. Rewrite the equation

(k+1/2009)(1+1/2+k) - (1+k+1/2009)(1/2+k)

4. Simplify

(k+1/2009)(k+3/2) - (k+2010/2009)(k+1/2)

5. Expand

[k^2 + (1/2009 + 3/2)k + (1/2009)(3/2)] - [k^2 - (2010/2009+1/2)k - (2010/2009)(1/2)]

6. Rewrite

(1/2009 + 3/2 - 2010/2009 - 1/2)k + (1/2009)(3/2) - (2010/2009)(1/2)

7. Simplify

(3/2 - 2009/2009 - 1/2)k + 1/2(3/2009-2010/2009)

8. Evaluate

0*k + 1/2(-2007/2009)

= -2007/4018

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.