For the function y = 3x2 - 12x + 4, what’s the mirror point for the y-intercept? remember to type your point in the form (x, y) without any spaces.,

(4,4).

Step-by-step explanation:

First find the axis of symmetry:

y = 3x^2 - 12x + 4

y = 3(x^2 - 4x) + 4

y = 3 [(x - 2)^2 - 4] + 4

y = 3(x - 2)^2 - 8

So the axis of symmetry is x = 2.

The y intercept of the function y is where x= 0 and y = 4  - that is (0,4).

The mirror point for the y intercept is the reflection  of (0,4) in the line x = 2.

That is  (2*2, 4) = (4,4).

where are the images of the functions i can only see the question you typed.

step-by-step explanation: