Write an equation in slope intercept form for the line that passes through (-4,2) parallel to 6x-3y=15

y=2x+10

Step-by-step explanation:

6x-3y=15subtract 6x from both sides

-3y=-6x+15then divide by -3 on all #'s

y=2x-5   m=2   b=(0,-5)

then y-y1=m(x-x1) points:(-4,2)

y-2=2(x+4)solve

y-2=2x+8add 2 to both sides(8+2)(-2+2)

y=2x+10

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

here is the

mark brainliest pl