Let f : r 3 → r be a scalar function and let f be a vector field in r 3 . assume that all derivatives exist and are continuous at all points. for each expression below, state whether it is

(a) not meaningful (i. e., not defined);
(b) a scalar function which is identically zero;
(c) a scalar function which is not necessarily identically zero;
(d) a vector field which is identically zero; or
(e) a vector field which is not necessarily identically zero. you do not have to justify your answers. (grad = gradient.)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

if you was gonna solve for a, a is a   < -12

hi how are you doing today? if you ever need just tell me

step-by-step explanation: