If the joint density function of x and y is f(x, y)=c(x2−y2)e−4x, with 0≤x< [infinity] and −x≤y≤x, find each of the following.

(a) the conditional probability density of x, given y=y> 0. conditional density fx|y(x, y)= (x^2-y^2)e^(4y-4x)/(y/8 + 1/32) (enter your answer as a function of x, with y as a parameter.)
(b) the conditional probability distribution of y, given x=x. conditional distribution fy|x(y|x)= (x^2 - y^2)/(4/3 x^3) (for −x≤y≤x). (enter your answer as a function of y, with x as a parameter.)

go hook jvc hgv cj xk jvc 6756

saving = more money

step-by-step explanation:

if you have 100 bucks, and you want to buy a candy bar, even if you have one at home, if you choose not to buy it, you save.

~courtney

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

75%

step-by-step explanation: