Air-usa has a policy of booking as many as 24 persons on an airplane that can seat only 22. (past studies have revealed that only 86% of the booked passengers actually arrive for the flight.)find the probability that if air-usa books 24 persons, not enough seats will be available. prob =is this probability low enough so that overbooking problems will be unusual? (define unusual as having probability 5% or less)a. yes, it is low enoughb. no, it is not low enough
what about defining unusual as 10% or less? a. no, it is not low enoughb. yes, it is low enough

B. no, it is not low enough

A. no, it is not low enough

Step-by-step explanation:

Given that Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22.

Prob for  a random person booked arrive for flight = 0.86

No of persons who books and arrive for flight, X is binomial, since there are two outcomes and each person is independent of the other

The probability that if Air-USA books 24 persons, not enough seats will be available

= P(X=23)+P(x=24)

= 0.1315

B. no, it is not low enough

The prob we got is >10% also

A. no, it is not low enough

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

its an acute right triangle

step-by-step explanation: