Suppose that weights of bags of potato chips coming from a factory follow a normal distribution with mean 12.8 ounces and standard deviation .6 ounces. if the manufacturer wants to keep the mean at 12.8 ounces but adjust the standard deviation so that only 1% of the bags weigh less than 12 ounces, how small does he/she need to make that standard deviation

std dev = 0.625

Step-by-step explanation:

Given that  weights of bags of potato chips coming from a factory follow a normal distribution with mean 12.8 ounces and standard deviation .6 ounces.

We must change std deviation such that

P(X<12) =0.01

Mean would remain the same as 12.8 oz

From normal distribution score we can find

10th percentile is -1.28\

i.e. we must have

Std deviation should be 0.625

4.6875 pounds

step-by-step explanation:

y-1700=200(x+4)

step-by-step explanation:

200(x+4) is 200x + 800 she is saving 200 per week x is the weeks and the -1700 is. us that’s howmuch she already had