A. j. has 20 jobs that she must do in sequence, with the times required to do each of these jobs being indepen-dent random variables with mean 50 minutes and standard deviation 10 minutes. m. j. has 20 jobs that he must do in sequence, with the times required to do each of these jobs being independent random variables with mean 52 min-utes and standard deviation 15 minutes.

( a) find the probability that a. j. finishes in less than 900 minutes.
( b) find the probability that m. j. finishes in less than 900 minutes.
( c) find the probability that a. j. finishes before m. j.

0.3085,0.3204,0.4558

Step-by-step explanation:

given that A. J. has 20 jobs that she must do in sequence, with the times required to do each of these jobs being indepen-dent random variables with mean 50 minutes and standard deviation 10 minutes

M. J. has 20 jobs that he must do in sequence, with the times required to do each of these jobs being independent random variables with mean 52 min-utes and standard deviation 15 minutes.

Let X stand for I one and Y for II one

a)  Find the probability that A. J. finishes in less than 900 minutes

=

b) Find the probability that M. J. finishes in less than 900 minutes.

=

c) Consider 90X-90Y. If A finishes before Mj then 20x-20Y>0

x-y>0

X-Y is normal with mean = -2 and variance =

Std dev = 18.03

Prob =

the answer is 375 miles

step-by-step explanation:

20%

step-by-step explanation: