Complete the table
time- 1 2 5 x
distance x x 25 100

Table is

Time-------Distance

 1---------------5

 2--------------10

 5--------------25

20------------100

Step-by-step explanation:

Given the table show value of time and distance.

Time-------Distance

 1--------------?

 2-------------?

 5------------25

 ?------------100

We know that formula for speed is given by

Here, The missing values are in 1sr, 2nd and 4th rows

For 3rd Row:

Distance=25m

Time=5min

Speed is given by

Speed = 5m/min

Using Value of speed,

We can find missing values

For 1st Row:

Speed: 5m/min

Distance=?

Time=1min

Speed is given by

Distance=5x1=5

A distance of 1st row is 5m

For 2nd Row:

Speed: 5m/min

Distance=?

Time=2min

Speed is given by

Distance=5x2=10

A distance of 1st row is 10m

For 4th Row:

Speed: 5m/min

Distance=100m

Time=?

Speed is given by

time=100/5=20

A time for 4th row is 20min

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.