Plz hurry it's

you randomly draw marbles from a bag containing both blue and green marbles, without replacing the marbles between draws. if b=drawing a blue marble and g=drawing a green marble, which represents the probability of drawing a blue marble first and a green marble second?

a. p(b)⋅p(g)

b. p(b and g)

c. p(g after b)

d. p(b, then g)

The correct option is

(D) P(B, then G).

Step-by-step explanation:  Given that we  randomly draw marbles from a bag containing both blue and green marbles, without replacing the marbles between draws.

Also, B = drawing a blue marble and G = drawing a green marble.

We are to select the option that represents the probability of drawing a blue marble first and a green marble second.

Since we are drawing the second marble without replacing the first drawn marble, so the event is of the form

"first, then second."

So, the probability is written as P(B, then G).

Thus, The required probability is P(B, then G).

Option (D) is CORRECT.

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!