Paula pidcoe is doing her budget. she discovers that the average miscellaneous expense is $65.00 with a standard deviation of $18.00. what percent of her expenses in this category would she expect to fall between $54.20 and $86.60?

68.65%

Step-by-step explanation:

Given : Paula Pidcoe discovers that the average miscellaneous expense is $65.00 with a standard deviation of $18.00.

i.e. and

We assume that the miscellaneous expenses follows normal distribution.

Let x denotes the miscellaneous expenses .

Then, the probability that  her expenses fall between $54.20 and $86.60 will be :

Hence, she would expect 68.65% of her expenses in this category to fall between $54.20 and $86.60 .

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

i dont have an answer

step-by-step explanation: