Find k such that the points (-2, 5), (2, 8) and (6, k) are collinear.

k = 11

Step-by-step explanation:

let the points be A(-2,5), B(2,8), C(6,K).

for the points to be collinear slope of line AB maust be equal to line BC.

slope of line AB =

slope of line BC =

therefore

therefore k = 8 + 3

k = 11

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

no ,sorry if you needed it but you can ask and try to see if any one will anwser ,

step-by-step explanation:

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have a nice day