Suppose the probability of being infected with a certain virus is 0.001. a test used to detect the virus is positive 99% of the time if the person test has the virus, and positive 5% of the time if the person does not have the virus. use bayes theorem to find the probability that a person is infected with the virus, given that they test positive. clearly show your work and how you are using the theorem.

0.0194

Step-by-step explanation:

Let's define the following events

A: a person is infected with the virus

B: a person test positive

: a person is not infected with the virus

We know that P(A) = 0.001, and then = 0.999. A test used to detect the virus is positive 99% of the time if the person test has the virus is equivalent to P(B|A) = 0.99. And positive 5% of the time if the person does not have the virus means =0.05. We want to find the probability that a person is infected with the virus, given that they test positive, i.e., P(A|B). Bayes Theorem tell us that =0.0194

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

y -5 = (-1/4)(x + 8)

step-by-step explanation: