Select all the correct locations on the table. select all the expressions with accurately written descriptions. 8 * (2y + 6) ^ 2 times the square of the sum of 2 times y and 6 2(9 + x) * (x - 7) ) 2 times the product of the sum of 9 and x and the difference of x and 7 (5x - 3) ^ 2 the square of the difference of 5 times x and 3 7x ^ 2 the square of the product of 7 and y ^ 2 + 3y - 4 the sum of y squared and three times y minus 4 5(8x ^ 2 + 20x + 8) the product of 5 and 8 plus the square of plus the sum of 20x and 8

d

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

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step-by-step explanation:

i think it is c hope that