What price do farmers get for their watermelon crops? in the third week of july, a random sample of 45 farming regions gave a sample mean of x = $6.70 per 100 pounds of watermelon. assume that σ is known and σ = $1.85 per 100 pounds of watermelon.

a) what conditions of the problem allow you to use the standard normal distribution (s. n.
b) find a 85% confidence interval for the population mean µ (in units of $ per 100 pounds) that farmers in this region get for their watermelon crop.
c) what is the maximal margin of error, e (in units of $ per 100 pounds) found in b)?
d) what does a 85% confidence interval mean mathematically?
e) find the sample size necessary for a 85% condence level with maximal margin of error e = $0.3 per 100 pounds for estimating the population mean µ (in units of $ per 100 pounds).

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

3 3 6, because in every triangle the longer side is always shorter than the sum of the other two