The cdc estimates that each year in the united states, on average, 5% to 20% of the population gets the flu. using 20% as our best guess (p∗), find how large a sample would be needed to get a ±2 percentage point margin on a 95% confidence interval for the population proportion of americans who get the flu in a given year.
a. 1536
b. 1537
c. 2401
d. 2402
e. 40

b. 1537

Step-by-step explanation:

When prior estimate of population proportion is available , then the formula for sample size:  

, where p= prior estimate of population proportion

z*= critical-value.

E= Margin of sampling error.

Let p be the proportion of population gets the flu.

As per given , we have

p=20%=0.20

E= ± 0.02

Using z-table , the critical z-value corresponding to 95% confidence level = z*=1.960

Substitute all the values in the above formula , we get

Required sample size  :

[Rounded to next integer.]

Thus, the minimum sample size needed = 1537

Hence, the correct answer =  b. 1537

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all