For the first 30 km, the bicyclist rode with a speed of v km/hour. for the remaining 17 km he rode with a speed which was 2 km/hour greater than his original speed. how much time did the bicyclist spend on the entire trip? let t be the time (in hours), and find t if:

a) v=15
b) v=18

The time spent by bicyclist on entire trip is

a) when v = 15 then t = 3 hours

b) when v = 18 then t = 2.52 hours

The time taken is given by formula:

For the first 30 km, the bicyclist rode with a speed of v km/hour

Here distance = 30 km and speed = v km\hour

Let denote time taken to cover first 30 km

For the remaining 17 km he rode with a speed which was 2 km/hour greater than his original speed

so the speed to cover next 17 km = v + 2

Let denote time taken to cover remaining 17 km

Now total time t spent by the bicyclist to cover entire trip is given by

total time "t" = time taken for first 30 km + time taken for remaining 17 km

We have to find value of "t" for a) v = 15 and b) v = 18

a) value of t when v = 15

Substitute v = 15 in eqn 1

t = 2 + 1 = 3

So t = 3 hours

b) value of t when v = 18

Thus t = 2.52 hours

1/2*qr*rs

step-by-step explanation: