Meanwhile, at the ballpark juan was practicing his hitting while talking to the girls standing around watching. he started telling them how he hit the ball over the 50 foot light tower yesterday. the girls were unsure that he really did that. the formula for this hit is:
h(x)=-16x^2+60x+4 where h is the height of the ball and x is the number of seconds the ball is in the air. how high did juan actually hit the ball?

5.2 seconds

Step-by-step explanation:

We want to determine the value of x when h(x) = 0

:

-16x^2 +83x + 4 = 0

:

use quadratic formula to determine the value for x

:

x = ( -83 + sqrt(83^2 - 4*(-16)*4) ) / (2*(-16) = −0.047753182

:

x = ( -83 - sqrt(83^2 - 4*(-16)*4) ) / (2*(-16) = 5.235253182

:

we want the positive value for x since time runs forward

:

the ball hung in the air for approx 5.2 seconds

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this