What is the equation of a line parallel to the x-axis that passes though the point (4,5)? what is the slope of this line

Slope of a line parallel to the x -axis is 0

y = 5 is the required equation of a line parallel to the x-axis that passes though the point (4,5)

Given that  a line parallel to the x-axis that passes though the point (4,5)

To find: slope of this line and equation of a line

The x -axis is a horizontal line with the equation y = 0 There are an infinite number of lines that are parallel to the x -axis, y = 0

All horizontal lines have slope of 0

If lines are parallel then they have the same slope. The slope of a line parallel to the x -axis is 0

The equation of a straight line parallel to x-axis at a distance b from it is y = b

Here "b" is the y - co-ordinate value

Here given point is (4, 5) so b = 5

The required equation is y = 5

We know slope "m" = 0

Given point is (4, 5)

The slope intercept form is given as:

y = mx + b --- eqn 1

Where "m" is the slope of line and "b" is the y - intercept

Substituting m = 0 and (x, y) = (4, 5)

5 = 0(4) + b

b = 5

Substitute b = 5  and m = 0 in eqn 1

y = 0 + 5

y = 5 is the required equation of a line parallel to the x-axis that passes though the point (4,5)

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation: