How to solve by substitution these nu
mbers x-6y=15 and 6x+5y=8

(3, - 2 )

Step-by-step explanation:

Given the 2 equations

x - 6y = 15 → (1)

6x + 5y = 8 → (2)

Rearrange (1) expressing x in terms of y by adding 6y to both sides

x = 15 + 6y → (3)

Substitute x = 15 + 6y into (2)

6(15 + 6y) + 5y = 8 ← distribute and simplify left side

90 + 36y + 5y = 8

90 + 41y = 8 ( subtract 90 from both sides )

41y = - 82 ( divide both sides by 41 )

y = - 2

Substitute y = - 2 into (3) for corresponding value of x

x = 15 + 6(- 2) = 15 - 12 = 3

Solution is (3, - 2 )

my computer is slow i can not see it sorry

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7