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select from the drop-down menus to correctly complete the proof.

to prove that 2√2 is irrational, assume the product is rational and set it equal to a/b, where b is not equal to 0: 2√2 = a/b . isolating the radical gives √2 = a/2b. the left side of the equation is (irrational, rational) . because the right side of the equation is (irrational, rational), this is a contradiction. therefore, the assumption is wrong, and the number 2√2 is (irrational, rational).

idk

step-by-step explanation: i just don't

17

step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076