answer:
ellipse with vertical major axis (x−h)2b2+(y−k)2a2=1
hyperbola with horizontal transverse axis (x−h)2a2−(y−k)2b2=1
hyperbola with vertical transverse axis (y−k)2a2−(x−h)2b2=1
parabola with horizontal axis (y−k)2=4p(x−h) , p≠0
step-by-step explanation:
(x − h)2 = 4p(y − k), p ≠ 0 vertical axis (y − k)2 = 4p(x − h), p ≠ 0 horizontal axis 15–24 (x − h)2 a2 + (y − k)2 b2 = 1 horizontal major axis (x−h)2b2 + (y−k)2a2 = 1 658). y = k ± b a(x − h) horizontal transverse axis y = k ± a b(x − h) vertical