Mathematics, 09.12.2019 20:31 JAYDENJONES0111
The blue diamond company advertises that their nut mix contains (by weight) 40% cashews, 15% brazil nuts, 20% almonds and only 25% peanuts. the truth-in-advertising investigators took a random sample (of size 20 lbs) of the nut mix and found the distribution to be as follows: 6 lbs of cashews, 3 lbs of brazil nuts, 5 lbs of almonds and 6 lbs of peanuts. at the 0.01 level of significance, is the claim made by blue diamond true? a) two sample t test for meansb) one sample z test for meansc) ? 2 goodness of fit testd) one sample z test for proportionse) one sample t test for meansf) two sample z test for proportionsg) matched pairs t testh) ? 2 test for independence
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The blue diamond company advertises that their nut mix contains (by weight) 40% cashews, 15% brazil...
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