Kris spent $131 on shirts. fancy shirts cost $28 and plain shirts cost $15. is kris bought a total of 7 then how many of each kind did she buy?

Number of fancy shirts Kris bought  = 2

Number of plain shirts Kris bought = 5

Step-by-step explanation:

Total number of shirts = 7

Let number of fancy shirts be =

Let number of plain shirts be =

Total number of shirts =

So, we have a sum equation as:

Total cost of shirts = $131

Cost of a fancy shirt = $28

Cost of  fancy shirts in dollars can be given as =

Cost of a plain shirt = $15

Cost of plain shirts in dollars can be given as =

Total cost of shirts =

So, we have a cost equation as:

The system of equations is :

A)

B)

Rearranging equation A, to solve for in terms of

Subtracting both sides by

Substituting value of we got from A into equation B.

Using distribution.

Simplifying.

Subtracting both sides by 105.

Dividing both sides by 13.

We can plugin in the rearranged equation A to get value of

∴

So, number of fancy shirts Kris bought  = 2

Number of plain shirts bough = 5

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}