Prove that joys with vertices j(1,1) o(2,-6) y(3,3) s(2,10) is a parallelogram

For this you're going to use distance formula

D= square root of (x2-x1)^2 + (y2-y1)^2

To prove this is a parallelogram ALL sides must equal the same or two sides + two sides must be the same.

Find the distance of JO, YS, JS, and OS. If you have too find the distance of JY and OY. Using the formula above. Hope this helps you. If you need further help I can assist you with a problem step by step

answer: f = 32.2m

step-by-step explanation: that is the answer

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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