The coordinate grid shows points a through k. what point is a solution to the system of inequalities? y ≤ −2x + 10 y > 1 over 2x − 2 coordinate grid with plotted ordered pairs, point a at negative 5, 4 point b at 4, 7 point c at negative 2, 7 point d at negative 7, 1 point e at 4, negative 2 point f at 1, negative 6 point g at negative 3, negative 10 point h at negative 4, negative 4 point i at 9, 3 point j at 7, negative 4 and point k at 2, 3 a b j h

The points which represents a the solution are: A, C, D and K

Step-by-step explanation:

See the attached figure.

The given inequalities:  y ≤ −2x + 10 & y > 1/(2x − 2)

The given points: A(-5,4), B(4,7), C(-2,7), D(-7,1), E(4,-2),

F(1,-6), G(-3,-10), H(-4,-4), I(9,3), J(7,-4) and K(2,3).

The attached figure represents the graph of the given inequalities.

The shaded area represents the solution of the inequalities.

So, the points lies in the shaded area represents the solution of the inequalities.

So, points A, C, D and K are a solution to the system of inequalities.

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Note:

If the given inequalities:  y ≤ −2x + 10 & y > (1/2x) - 2

It will be the same solution.

The correct answer is A which is A

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step-by-step explanation:

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the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0