Determine the total revenue earned by selling x calculator if the price per calculator is given by the demand function p = 150 - 0.4x. how many calculators must be sold to maximize the total revenue?

The revenue is maximum around 187.5 that means we can sell 187 or 188 calculators to get the maximum revenue.

Step-by-step explanation:

Let the total number of calculators sold = x

The price per demand of calculator , p =150 - 0.4x

Total revenue =

                        =

To maximize revenue, derivative of total revenue must be zero.

= 0

150 - 0.4x - 0.4x = 0

150 - 0.8x = 0

0.8x = 150

x = 187.5

So the revenue is maximum around 187.5 that means we can sell 187 or 188 calculators to get the maximum revenue.

Maximum revenue =

                                =14,062.4

what are the things "represented below"?

step-by-step explanation:

nobody can if you dont give the choices

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.