Parnell unvested a total of $14000 in two accounts. after a year, one account lost 7.7% while the other account gained 2.5%. in total, parnell lost $517. write a system of equations to find how much money parnell invested in each account.

the equations are

x + y = 14000

0.077x - 0.025y = 517

Step-by-step explanation:

Let x represent the amount invested in first account.

Let y represent the amount invested in second account.

Parnell invested a total of $14000 in two accounts. It means that

x + y = 14000

After a year, first account lost 7.7%. The amount lost in the first account is 7.7/100 × x = 0.077x.

The amount left in the first account is

x - 0.077x = 0.923x

On the other account gained, he gained 2.5%.

The amount gained in the second account is 2.5/100 × y = 0.025y

The amount left in the first account is

y + 0.025y = 1.025y

Total amount in first account and second account presently is

0.923x + 1.025y

Total amount in first account and second account initially is

x + y

Amount lost is

x + y - (0.923x + 1.025y)

= 0.077x - 0.025y

In total, Parnell lost $517. Therefore

0.077x - 0.025y = 517

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.