When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. when a certain constant force acts upon an object with mass 6 kg, the acceleration of the object is 7 /ms2. if the same force acts upon another object whose mass is 14 kg, what is this object's acceleration?

a = 3 m/s^2

Step-by-step explanation:

Let the acceleration of the object be represented by a

Let the constant force acting on the object be represented by k

Let the mass of the object represented by m

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. This means that

a = k/m

When a certain constant force acts upon an object with mass 6 kg, the acceleration of the object is 7 /ms2. It means that when a = 7, m = 6. We would find k. Therefore

7 = k/6

k = 7×6 = 42

The expression becomes

a = 42/m

If the same force acts upon another object whose mass is 14 kg, it means that m = 14, then

a = 42/14 = 3

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.