The top and bottom margins of a poster are 6 ft and the side margins are each 8 ft. if the area of printed material on the poster is fixed at 386 square ft, find the dimensions of the poster with the smallest area.

Dimension

Height =29.01

Breadth=38.70

Step-by-step explanation:

Printed area is =386 and margins as specified.

For printed area let height be x and breadth be y.

x*y=386 ⇒ y =

Now considering the margins

Height = x+6+6=x+12

Weidth = +8 +8= + 16

Area of poster to be minimised =(x+12)( + 16)

Differentiate above area with respect to x and equate to zero to find extrema.

  = 16 -=0

x=17.01

Now plug value of x in height and breadth

 Height =29.01

Breadth=38.70

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6