The half-life of sodium-22 is 2.6 years. a sample contains 800 mg of this isotope.

which expression represents the mass of sodium remaining after h half-lives?

s = 0.5(800)h

s = 800(0.5)h

s = 8000.5h

s = 800h + 0.5
which expression relates h, the number of half-lives, and y, the number of years?

The answer is B S=800(0.5)h

Which expression relates h, the number of half-lives, and y, the number of years? Answer h=y/2.6

Combine the first two equations and laws of exponents to find the equation for the mass of sodium remaining after y years. Answer S=800(0.766)y

Approximately how many milligrams of sodium remain after 8.4 years? Answer 85.2 mg

Step-by-step explanation:

answer: .75 km

step-by-step explanation: