Will give brainliest if both are correct

these are two separate questions that have nothing to do with each other.

find the constant of variation k for the direct variation.

x | f(x)

-1 | 2

0 | 0

2 | -4

5 | -10

a) k = –0.5

b) k = 2

c) k = –1.5

d) k = –2



question 2

does the data in the table represent a direct variation or an inverse variation? write an equation to model the data in the table.

|_2__|__4__|__8__|__12__|

|_4__||__1__|__2/3_|

a) direct variation; y = 8/x

b) direct variation; y = 8x

c) inverse variation; xy = 8

d) inverse variation; y/x = 8

Q1) D

Q2) C

Step-by-step explanation:

Q1)

y ∝ x

y = kx

Let x=-1,y=2

2 = k(-1)

k = -2

Q2)

directly (y=kx)

Let x=2,y=4

4 = k(2)

k = 2

y = 2x

inverse (y = k/x)

Let x=2,y = 4

4 = k/2

k = 8

xy = 8

your answer would be b

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3