Apersonnel director interviewing 11 senior engineers for four job openings has scheduled six interviews for the first dayand five for the second day of interviewing. assume that the candidates are interviewed in random order. a. what is the probability that x of the top four candidates are interviewed on the first day? b. how many of the top four candidates can be expected to be interviewed on the first day?

$2,703.06

step-by-step explanation:

add: $2,687.44+ $2,613.09+$2,808.64= $8,109.17

divide by 3 because you added 3 numbers.

$8,109.17/3=

answer: $2,703.06

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.