The measure of an angle of an isosceles triangle is 30°, the shorter side is 20 in. find a distance from point p to the vertex of a triangle, if p is equidistant from all vertices.

the angles in this triangle are 30, 30, and 120. the shorter sides are 20 inches. if P is equidistant from all vertices, it has to be outside of the triangle. We can name the points in the triangle A, B, and C.

You get a quadrilateral if you connect the lines from P to B and P to C. You can get two isosceles triangles from this, APC and APB. In triangle APC, lines AP and CP are equal, and in triangle APB lines AP and BP are equal. The base sides in each of these triangles are 20 inches, and the base angles are 60 degrees, meaning these are equilateral triangles.

HENCE, PA IS EQUAL TO 20 INCHES.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )