Determine whether each relation is an equivalence relation. justify your answer. if the relation is an equivalence relation, then describe the partition defined by the equivalence classes.

(a)

the domain is a group of people. person x is related to person y under relation p if x and y have a common parent (i. e., x and y have the same biological mother or the same biological father or both). you can assume that there is at least one pair in the group, x and y, such that xpy.

(b)

the domain is a group of people. person x is related to person y under relation m if x and y have the same biological mother. you can assume that there is at least one pair in the group, x and y, such that xmy.

last one.

step-by-step explanation:

last one.

generally speaking, the others follow some sort of pattern that correlates to either linear (looks like a straight line) or sinusoidal (looks like an s).

the last one is just a random cloud of points that doesn't correlate to any particular known order.

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200

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