Suppose that the position of one particle at time t isgiven by the equations x1 andy1. meanwhile, the position of a secondparticle is given by the equations x2 andy2.
x1 = 3sin(t)
y1 = 2cos(t)
0 ≤ t ≤ 2π

x2 = -3 +cos(t)
y2 = 1 + sin(t)
0 ≤ t ≤ 2π

(a) graph the paths of both particles. (do this on paper. yourinstructor may ask you to turn in this work.) how many points ofintersection are there?
(b) find the collision point, where the particles are atthe same place at the same time.
(c) if the x-coordinate of the second particle is given byx2 = 3 +cos(t) instead, is there still a collision?

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yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36