Can someone pls me with my hmwk? do as many as you can anything
it's an inequality so it's solved like
1/3j ≤ 4
•3 •3
= =
j 12
25) 12c ≤ -144
27) 6b ≥ 3/5
29) b/8 ≤ -2
31) 1/2 < r/-3
33) y/-4 > -1/2
35) -2.25t < -9
37) -11z > 121
39) -k ≥ 7
41) 16 ≥ -4/3p
43) -8x < 24
45) 1/4x < 5
47) 45 ≤ -9p
49) -3/4b > -3/2
51) the product of a number and 7 is not less than 21
53) the product of -4/5 and b is at most -16
55) the area of a rectangle is at most 21 square inches. the width of the rectangle is 3.5 inches. what are the possible measurements for the length of the rectangle?
sorry for all the work you so much due tomorrow ; -;

25)In order to bring this inequality to graphable form, we need to move all the terms to the left side.In my example, term -144, will be moved to the left side.

Notice that a term changes sign when it 'moves' from one side of the inequality to the other. so it will be written as 12c+144≤0 and ur answer will be

c ≤ -12

27) term 3/5, will be moved to the left side. so it will be written like this 6b+(-3/5) ≥ 3/5 + (-3/5). then it will be written as 5(6b) + (-3)/5 ≥ 3/5 - 3/5, and ur answer will be

b ≥ 1/10

29) In order to factor an integer, we need to repeatedly divide it by the ascending sequence of primes (2, 3, 5...).The number of times that each prime 'goes into' the original integer becomes its exponent in the final result.     Prime number 2 goes into 8 three times. So it will be written like this, b/8 + 2 ≤  -2 + 2, and then b/2^3 + 2 ≤ 0 and ur answer will be

b ≤ -16

31) We need to get rid of all the denominators in this inequality. This can be achieved by multiplying both the left and the right side by the Least Common Denominator. In my example, the LCD is equal to 2 x 3. So it will be written like this, 3 < 2 (-r), and then 3 < -2r and ur answer will be, rin(-\infinity ,-3/2)

Step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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