Suppose that in sampling for the population proportion, it is found that 20 out of 100 items are defective. construct a 95% confidence interval for the proportion of defective items in the population

(0.1216,0.2784)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

, where = Sample proportion.

n= sample size.

z* = critical z-value.

Given : sample size = 100

Sample proportion of defective items =

Confidence level =95%

We know that , Critical z-value for 95% confidence interval  = 1.96

Then, the confidence interval for the proportion of defective items in the population will be :-

Hence, the 95% confidence interval for the proportion of defective items in the population =  (0.1216,0.2784)

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: